TAMPA, Fla. – The Tampa Bay Buccaneers feel good about their chances of repeating as Super Bowl champions and aren't wasting time doing whatever's necessary to retain key components of their roster to help Tom Brady pursue an eighth NFL title.
Linebacker Shaquil Barrett and tight end Rob Gronkowski, who came out of retirement 11 months ago to help Brady win No. 7 in his first season with the Bucs, are the latest players to agree to terms to stay with the team.
Agent Drew Rosenhaus represents both players and confirmed the deals to The Associated Press on Monday.
Barrett agreed to a four-year, $72 million contract. Gronkowski will return for his 11th season with Brady on a one-year, $10 million deal — up from the $9.25 million he earned after arriving in Tampa Bay from the New England Patriots in a trade last April.
Barrett has been one of the NFL’s top pass rushers over the past two seasons and earned $15.8 million in 2020, when he played under the franchise tag after leading the league with 19½ sacks in 2019.
The 28-year-old’s new deal — facilitated by Brady signing an extension that cleared $19 million in salary cap space — includes $36 million guaranteed, Rosenhaus said.
The moves Monday were the fourth and fifth general manager Jason Licht and coach Bruce Arians have made in the past week to ensure key players on the verge of becoming unrestricted free agents would not wind up testing their worth on the open market.
The team placed the franchise tag on wide receiver Chris Godwin and signed linebacker Lavonte David to a salary-cap friendly, two-year deal worth up to $25 million before Brady agreed to an extension that will keep the three-time NFL MVP under contract through 2022.